A 300 liter of solution is made by mixing 180g of sodium chloride in w

1.	A 300 liter of solution is made by mixing 180g of sodium chloride in water. calculate the concentration of the solution?
Answer» Answer: 1.027 × 10⁻² M Explanation: Given : Volume of solution = 300 L Given MASS of NaCl = 180 G We have molar mass of NaCl = 58.44 g / mol Now : No. of moles n = 180 / 58.44 mol We are asked to find concentration of the solution! Molarity is term of concentration which defined as no. of moles of SOLUTE present in unit volume of solution in litre. = > M = n / V ( L ) = > M = 180 / ( 58.44 × 300 ) M = > M = 6 / ( 58.44 × 10 ) M = > M = ( 6 / 5.844 ) × 10⁻² M = > M = 1.027 × 10⁻² M Hence we get required answer.

A 300 liter of solution is made by mixing 180g of sodium chloride in water. calculate the concentration of the solution?

Answer»

1.027 × 10⁻² M

Given :

Volume of solution = 300 L

Given MASS of NaCl = 180 G

We have molar mass of NaCl = 58.44 g / mol

Now :

No. of moles n = 180 / 58.44 mol

We are asked to find concentration of the solution!

Molarity is term of concentration which defined as no. of moles of SOLUTE present in unit volume of solution in litre.

= > M = n / V ( L )

= > M = 180 / ( 58.44 × 300 ) M

= > M = 6 / ( 58.44 × 10 ) M

= > M = ( 6 / 5.844 ) × 10⁻² M

= > M = 1.027 × 10⁻² M