1.

→A=3^i+2^j+7^k →B=^i−6^j+5^k →C=−2^i+^j−4^k Find 2→A−→B+3→C

Answer»

A=3^i+2^j+7^k

B=^i6^j+5^k

C=2^i+^j4^k

Find 2AB+3C




Discussion

No Comment Found