1.

A=3+b then find the value of a³-b³-9ab

Answer»

a=3+b

taking CUBE on both SIDES

a^3=27+b^3+27b+9b^2

a^3=27+b^3+9b(3+b)

a^3=b^3+27+9ab

a^3-b^3-9ab=27

hence PROVED....



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