a 27 g sample of an unknown hydrocarbon was burner in excess O2 to form 88 g of CO2 and 27 g of h2o . what is possible molecular formula of hydrocarbon ch4 c2h2 c4h3 c4h

a 27 g sample of an unknown hydrocarbon was burner in excess O2 to for

1.	a 27 g sample of an unknown hydrocarbon was burner in excess O2 to form 88 g of CO2 and 27 g of h2o . what is possible molecular formula of hydrocarbon ch4 c2h2 c4h3 c4h
Answer» C2H3Explanation:Let US first write the chemical equation of the given problem in a GENERIC way;CH + O2 == CO2 + H2O.Now the number of moles of CO2 produced = 88 / 44 = 2.And the number of moles of WATER produced = 27/18 = 1.5.Now consider the generic equation, let us define the molecules of C and H. Let C have x molecules and H have y. We can write equation as;CxHy +(x+y/4) O2== x CO2 + y/2H2O.Now if we compare the above equation with number of moles of CO2 and H20, we can say that;C = 2.Y = 3Hence the HYDOCARBON would be C2H3