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A 25 watt bulb emits monochromatic yellow light of wavelength of ` 0. 57 mu` m. Calculate the rate of emission of quanta per second . |
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Answer» `25 W=25 J s^(-1)` Energy of one photon `(E)=hv` `=hc/lambda=(6.62xx10^(-34)xx10^(8))/(0.57xx10^(-6))` Rate of emission of equanta per second `=(25)/(6.62xx10^(-34)xx3xx10^(8))xx0.57xx10^(-6)` `=7.18xx10^(19) s^(-1)`. |
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