1.

A 25 watt bulb emits monochromatic yellow light of wavelength of ` 0. 57 mu` m. Calculate the rate of emission of quanta per second .

Answer» `25 W=25 J s^(-1)`
Energy of one photon `(E)=hv`
`=hc/lambda=(6.62xx10^(-34)xx10^(8))/(0.57xx10^(-6))`
Rate of emission of equanta per second
`=(25)/(6.62xx10^(-34)xx3xx10^(8))xx0.57xx10^(-6)`
`=7.18xx10^(19) s^(-1)`.


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