A 238U nucleus decays by emitting an alpha particle of speed ′v′ ms−1. The recoil speed of the residual nucleus (in ms−1 ) is:

A 238U nucleus decays by emitting an alpha particle of speed ′v′ m

1.	A 238U nucleus decays by emitting an alpha particle of speed ′v′ ms−1. The recoil speed of the residual nucleus (in ms−1 ) is:
Answer» A $^{238} U$ nucleus decays by emitting an alpha particle of speed $^{'} v^{'} m s^{- 1}$ . The recoil speed of the residual nucleus (in $m s^{- 1}$ ) is:

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A 238U nucleus decays by emitting an alpha particle of speed ′v′ ms−1. The recoil speed of the residual nucleus (in ms−1 ) is:

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