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A 200 V varialbe frequency a.c. source is connected to a series combination the angular `C = 80 mu F` and `R = 40 Omega`. Calculate the angular frequency of the soucre to get maximum current in the cicuit, the current amplitude at resonance and power dissipated in the circuit. |
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Answer» Here, `E_(v) = 200 V, L = 5 H, C = 80 xx 10^(-6) F` `R = 40 Omega`, To get maximum current, `omega = (1)/(sqrt(LC)) = (1)/(sqrt(5 xx 80 xx 10^(-6))) = (1000)/(20) = 50 rad//s` `I_(0) = (E_(0))/(Z) = (sqrt2 E_(v))/(R ) = (1.414 xx 200)/(40) = 7.07 A` `P = (E_(V)^(2))/(R ) = (200 xx 200)/(40) = 1000 W` |
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