A 200 ml mixture of CO and `CO_2` is passed through excess of red hot charcoal causing the following reaction. `CO_2(g)+C(s) to 2CO(g)` After passing the gas through charcoal , volume increased to 270 ml. Select the correct statement.A. Volume percentage of CO in the original mixture is 65%B. If original mixture was passed through KOH solution volume would have reduced to 70 mlC. Mole fraction of `CO_2` in the original mixture will be 0.25.D. Minimum moles of red hot charcoal required for complete conversion of `CO_2` should be 70 millimoles.

A 200 ml mixture of CO and `CO_2` is passed through excess of red hot

1.	A 200 ml mixture of CO and `CO_2` is passed through excess of red hot charcoal causing the following reaction. `CO_2(g)+C(s) to 2CO(g)` After passing the gas through charcoal , volume increased to 270 ml. Select the correct statement.A. Volume percentage of CO in the original mixture is 65%B. If original mixture was passed through KOH solution volume would have reduced to 70 mlC. Mole fraction of `CO_2` in the original mixture will be 0.25.D. Minimum moles of red hot charcoal required for complete conversion of `CO_2` should be 70 millimoles.
Answer» Correct Answer - A::C

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