A 20 gram bullet moving at 300 m/s stops after penetrating 3 cm of a bone. calculate the avg force exerted by the bullet.

A 20 gram bullet moving at 300 m/s stops after penetrating 3 cm of a b

1.	A 20 gram bullet moving at 300 m/s stops after penetrating 3 cm of a bone. calculate the avg force exerted by the bullet.
Answer» The initial velocity of BULLET is 300m/s. Final velocity=0 Distance covered=3cm=0.03m So,using the FORMULA v^2=u^2-2as We have 0=(300)^2-2a(0.03) Or 0.06a=90000 => a=90000/0.06 => a= 1500000m/s^2. So force =mass times ACCELERATION =(0.02kg)(1500000) =30000N

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A 20 gram bullet moving at 300 m/s stops after penetrating 3 cm of a bone. calculate the avg force exerted by the bullet.

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