-a^2*x %2B a^2*(b^2*x^2) %2B b^2*x - 1=0 – InterviewSolution

1.

-a^2x %2B a^2(b^2x^2) %2B b^2x - 1=0

Answer»

a^2b^2x^2 + b^2x - a^2x - 1 = 0

b^2x(a^2x - 1) - 1(a^2x + 1) = 0

(b^2x - 1)(a^2x + 1) = 0

x = 1/b^2, - 1/a^2

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