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(a)2 +( b)2+(c)2_ab_2bc_2ca=0, prove. That a=b=2c |
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Answer» ong>Answer: hope it helps Step-by-step explanation: a²+b²+4c²-ab-2bc-2ca=0 2(a²+b²+4c²-ab-2bc-2ca)=2(0) 2a²+2b²+8c²-2ab-4bc-4ca=0 (a²-2ab+b²)+(b²-4bc+4c²)+(4c²-4ca+a²)=0 (a-b)²+(b-2c)²+(2c-a)²=0 a-b=0 ; b-2c=0 ; 2c-a=0 a=b ; b=2c ; 2c=a a=b=2c hence proved |
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