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A^2+16a+63 factorise it |
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Answer» Answer: Reformatting the input : Changes made to your input should not affect the solution: (1): "a2" was replaced by "a^2". STEP 1 : TRYING to factor by splitting the middle term 1.1 Factoring a2-16a+63 The FIRST term is, a2 its coefficient is 1 . The middle term is, -16a its coefficient is -16 . The last term, "the constant", is +63 Step-1 : Multiply the coefficient of the first term by the constant 1 • 63 = 63 Step-2 : Find two factors of 63 whose sum equals the coefficient of the middle term, which is -16 . -63 + -1 = -64 -21 + -3 = -24 -9 + -7 = -16 That's it Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and -7 a2 - 9a - 7a - 63 Step-4 : Add up the first 2 terms, pulling out like factors : a • (a-9) Add up the last 2 terms, pulling out common factors : 7 • (a-9) Step-5 : Add up the four terms of step 4 : (a-7) • (a-9) Which is the DESIRED factorization Final result : (a - 7) • (a - 9) Step-by-step EXPLANATION: Mark as BRAINLIST [email protected] |
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