A 1m long wire having tension of 100 N and of linear mass density 0.01 kg/m is fixed and A and free at end B. the point C which is 20cm from end B is constrained to be stationary. To create resonance in the wire, the minimum frequency of the tuning fork will be :

A 1m long wire having tension of 100 N and of linear mass density 0.01

1.	A 1m long wire having tension of 100 N and of linear mass density 0.01 kg/m is fixed and A and free at end B. the point C which is 20cm from end B is constrained to be stationary. To create resonance in the wire, the minimum frequency of the tuning fork will be :
Answer» 125 Hz 150 Hz 300 Hz 275 Hz Solution :Length of BC to AC is `(20)/(80)=(1)/(4)` So, value of loops in BC to AC will also be `1 : 4` `f_(1)=(1)/(4(0.2))sqrt((T)/(mu))=125 Hz` `f_(2) = (3)/(4(0.2))sqrt((T)/(mu))=275 Hz`.

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A 1m long wire having tension of 100 N and of linear mass density 0.01 kg/m is fixed and A and free at end B. the point C which is 20cm from end B is constrained to be stationary. To create resonance in the wire, the minimum frequency of the tuning fork will be :

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