1.

(a) 17061. Find that smallest number which when divided by 5,6,8,9 and 12 leaves1 as remainder in each case but leaves no remainder when it is dividedby 13.

Answer»

lcm(5,6,8,912)=360.Hence 361 is divided by 5,6,8,9, 12 we get the remainder as 1.Find a positive integer 360*n+1 such that 13 divides that number. such a n is 10.Hence 3601 is the required number.



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