1.

a 16m deep well with diameter 3.5m is dug up and the earth out of it is spread evenly to form a plateform 27.5m by 7m . Find the height of the platform.​

Answer»

wer : 0.8 m✔✔

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Solution :

As we KNOW that :

Well is in the shape of CYLINDER

GIVEN that :

Height of well = 16 m.

And Diameter = 3.5m => Radius = 3.5/2 = 1.75 m

Now, Volume of Well (Cylinder) :

\pi {r}^{2} h \\ \\ = > \frac{22}{7} \times {(1.75)}^{2} \times 16....(1)

Also Given that :

As the well SPREAD evenly to form a plateform

Let, the height of plateform be x m.

Volume of plateform :

27.5 \times 7 \times x = 192.5x

ATQ :

\frac{22}{7} \times {(1.75)}^{2} \times 16 = 192.5x \\ \\ = > x = \frac{22 \times 1.75 \times 1.75 \times 16}{7 \times 192.5} = 0.8

So, the height of plateform will be 0.8 m. ✔

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Hope it helps ☺

Fóllòw Më ❤


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