(a) 1665(b) 14059. The product of two numbers is 360 and their H.C.F i

1.	(a) 1665(b) 14059. The product of two numbers is 360 and their H.C.F is 4. The L.C.M of the numbers is(a) 1860(b) 90(c) 1200(e) None of these(d) 48
Answer» Answer: 90 Step-by-step EXPLANATION: HCF×LCM=product of two integers HCF(a,B) × LCM(a,b)=a×b 4×LCM(a,b)=360 LCM(a,b)=360/4 LCM(a,b)=90

(a) 1665(b) 14059. The product of two numbers is 360 and their H.C.F is 4. The L.C.M of the numbers is(a) 1860(b) 90(c) 1200(e) None of these(d) 48

Answer»

Answer:

Step-by-step EXPLANATION:

HCF×LCM=product of two integers

HCF(a,B) × LCM(a,b)=a×b

4×LCM(a,b)=360

LCM(a,b)=360/4

LCM(a,b)=90

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(a) 1665(b) 14059. The product of two numbers is 360 and their H.C.F is 4. The L.C.M of the numbers is(a) 1860(b) 90(c) 1200(e) None of these(d) 48​

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(a) 1665(b) 14059. The product of two numbers is 360 and their H.C.F is 4. The L.C.M of the numbers is(a) 1860(b) 90(c) 1200(e) None of these(d) 48