1.

A 15gm ball is shot from a spring gun whose spring has a force constant 600 N//m. The spring is compressed by 5cm. The greatest possible horizontal range of the ball for this compression is (g = 10 m//"sec")

Answer»

Solution :`R_("max")= (u^(2))/(g)`……………(1)
But K.E acquired by ball = P.E of SPRING gun
`IMPLIES (1)/(2)MU^(2)= (1)/(2)kx^(2) implies u^(2)= (kx^(2))/(m)`……(2)
From equation (1) and (2)
`R_("max")= (kx^(2))/(mg)= (600 XX (5 xx 10^(-2))^(2))/(15 xx 10^(-3) xx 10)= 10cm`


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