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A 15gm ball is shot from a spring gun whose spring has a force constant 600 N//m. The spring is compressed by 5cm. The greatest possible horizontal range of the ball for this compression is (g = 10 m//"sec") |
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Answer» Solution :`R_("max")= (u^(2))/(g)`……………(1) But K.E acquired by ball = P.E of SPRING gun `IMPLIES (1)/(2)MU^(2)= (1)/(2)kx^(2) implies u^(2)= (kx^(2))/(m)`……(2) From equation (1) and (2) `R_("max")= (kx^(2))/(mg)= (600 XX (5 xx 10^(-2))^(2))/(15 xx 10^(-3) xx 10)= 10cm` |
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