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A `15.0 mu F` capacitor is connected to a 220 V, 50 Hz source. Find the capacitative reactance and the current (rms and peak) in the circuit. If the frequency is doubled. What happens to the capactive reactance and current ? |
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Answer» Here, `C = 15.0 mu F = 15 xx 10^(-6) F` `E_(v) = 220 V, v = 50 Hz, X_(C ) = ?` `I_(v) = ?, I_(0) = ?` `X_(C ) = (1)/(omega C) = (1)/(2 pi v C) = (1)/(2 xx (22)/(7) xx 50 xx 10^(-6))` `= (7 xx 10^(4))/(22 xx 15) = 212 ohm` `I_(v) = (E_(v))/(X_(C )) = (220)/(212) = 1.04 A`, `I_(0) = sqrt 2 I_(v) = 1.414 xx 1.04 = 1.47 A` When frequency is doubled, `X_(C)` is halved and current is doubled. |
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