1.

A) 13(x + 20) = 39b) 10(x-2)-4(x+1)+3(x+6)=0c)2{(x+1)+(x+2)}={(x+3)+(x+4)}​

Answer»

Step-by-step explanation:

(i) 13(X + 20) = 39

→ 13x + 260 = 39

→ 13x = 39 - 260

→ 13x = - 221

→ x = - 121/13

→ x = -17

(II) 10(x-2)-4(x+1)+3(x+6)=0

→ 10x - 20 - 4X - 4 + 3x + 18 = 0

→ (10x + 3x - 4x) + (18 - 20 - 4) = 0

→ 9x + ( -6) = 0

→ 9x - 6 = 0

→ 9x = 6

→ x = 6/9

→ x = ⅔

(iii) 2{(x+1)+(x+2)}={(x+3)+(x+4)}

→ 2{ x + 1 + x + 2 } = { x + 3 + x + 4 }

→ 2{2x + 3} = { 2x + 7 }

→ 4x + 6 = 2x + 7

→ 4x - 2x = 7 - 6

→ 2x = 1

→ x = ½


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