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A `120 V` house circuit has the following light bulbs switched on : `40 W, 60 W` and `75 W`. Find the equivalent resistance of these bulbs. |
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Answer» Correct Answer - A::B `P=V^2/R` `:. R=V^2/P` `R_1=((120)^2)/40=360Omega` `R_2=((120)^2)/60=240Omega` `R_3=((120)^2)/75=192Omega` Now, all these resistors are in parallel. |
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