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A 120 mm diameter jet of water is discharging from a nozzle into the air at a velocity of 40 m/s. The power in the jet with respect to a datum at the jet will be (a) 380 kW (b) 360 kW (c) 340 kW (d) 320 kW |
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Answer» Correct option is (b) 360 kW d = 120 mm V = 40 m/s Power = \(\cfrac12\) mv12 = \(\cfrac12\) pav13 = \(\cfrac12\) x 1000 x \(\left(\cfrac{\pi}4\times0.12^2\right)\) x 403 Power = 360 kW |
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