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A 10kg body suspended by a rope is pulled by horizontal force to make an angle of 60 |
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Answer» Your question is quite incomplete. According to the given data , As MASS and angle both are given then we NEED to find the horizontal FORCE F = ? As given . Mass = 10 kg. g = 10 m /sec² θ= 60° We know the formula F =mg cosθ Now put the VALUE in the formula . F = 10 × 10 COS 60° F = 100 × cos 60° F = 100/2 F = 50 N. Hope it Helps :-) |
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