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A 100 watt bulb emits monochromatic light of wavelength 400 nm. Calculate the number of photons emitted per second by the bulb. |
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Answer» E = \(\frac{hc}{\lambda}\) = \(\frac{6.626\times10^{-34}Js\times3\times10^8m^{-1}}{400\times10^{-9}}\) = 4.969 × 10−19J Power of the bulb = 100watt = 100Js−1 Number of Photons emitted = \(\frac{100\,Js^{-1}}{4.969\times10^{-19}J}\) = 2.012 × 1020 Photons. |
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