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A 100 W bulb `B_1`, and two 60 W bulb `B_2` and `B_3`, are connected to a 250 V source, as shown in figure. Now `W_1, W_2 and W_3` are the output powers of the bulbs `B_1, B_2 and B_3`, respectively. Then A. `W_1 gt W_2=W_3`B. `W_1gtW_2gtW_3`C. `W_1 lt W_2=W_3`D. `W_1 lt W_2 lt W_3` |
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Answer» `P=V^2/R` so, `R=V^2/P` `:. R_1=V^2/100` and `R_2=R_3=V^2/60` Now, `W_1=((250)^2)/((R_1+R_2)^2)R_1` `W_2=((250)^2)/((R_1+R_2)^.R_2` and `W_2=((250)^2)/R_3` `W_1:W_2:W_3=15:25:64 or W_1gtW_2gtW_3` `:.` The correct option is d. |
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