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A `100 mu F` capacitor is charged with a 50 V source supply. Then source supply is removed and the capacitor is connected across an inductor, as a result of which 5 A current flows through the inductance. Calculate the value of inductance. |
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Answer» Here, `C = 100 mu F = 10^(-4) F`, `V = 50` volt, `I = 5 A, L = ?` As energy stored in inductor = energy stored in capacitor, `:. (1)/(2) LI^(2) = (1)/(2) CV^(2)` `L = (CV^(2))/(I^(2)) = (10^(-4) (50)^(2))/((5)^(2)) = 0.01 H` |
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