A 10 m long wire ofresistance `20 Omega` is connected in series with battery of EMF `3V` and negligible internal resistance and a resistance of `10 Omega`. The potential gradient along the wire is :A. 0.02B. 0.1C. 0.2D. 1.2

A 10 m long wire ofresistance `20 Omega` is connected in series with b

1.	A 10 m long wire ofresistance `20 Omega` is connected in series with battery of EMF `3V` and negligible internal resistance and a resistance of `10 Omega`. The potential gradient along the wire is :A. 0.02B. 0.1C. 0.2D. 1.2
Answer» Correct Answer - C As resistances are in series, `R_("total")=R_(1)+R_(2)=20+10=30 Omega` `i=(4)/(R_("total"))=(3)/(30)=(1)/(10)A` So, `V_("wire")=iR_("wire")=(1)/(10)xx20=2V` Hence, potential gradient is `(V_("wire"))/(l)=(2)/(10)=0.2 Vm^(-1)`

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A 10 m long wire ofresistance `20 Omega` is connected in series with battery of EMF `3V` and negligible internal resistance and a resistance of `10 Omega`. The potential gradient along the wire is :A. 0.02B. 0.1C. 0.2D. 1.2

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