1.

A 10 kg rock is dropped and hits the ground below at a speed of 60 m/s. Calculate the gravitational potential energy of the rock before it was dropped. You can ignore the effects of friction.

Answer»

Solution:

MASS of body, m= 10kg

velocity, v= 60m/s

Now,kinetic ENERGY on earth= potential energy at a that POINT [energy conservation]

so, kinetic energy= 1/2*m* v^2

= 1/2* 60(60)^2

= 30* 60*60

= 108000 JOULES



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