1.

A 10 kg object collides with a stationary 5 kg object and after collision, they stick together and move forward with velocity 4 ms^(-1). What is the velocity with which the 10 kg object hits the second one ?

Answer»

`4 MS^(-1)`
`6 ms^(-1)`
`10 ms^(-1)`
`12ms^(-1)`

Solution :Here `m_1 = 10 kg, m_2 = 5 kg, u_1 = ? , u_2 = 0, V = 4 m//s`
Applying the principle of conservation of linear momentum,
`m_1u_1 + m_2u_2 = (m_1 + m_2)v , 10 u_1+ 5 xx 0 = (10 + 5) 4`
`10 u_1 = 60 " or " u_1 = 60/10 = 6 ms^(-1)`.


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