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A 10 kg object collides with a stationary 5 kg object and after collision, they stick together and move forward with velocity 4 ms^(-1). What is the velocity with which the 10 kg object hits the second one ? |
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Answer» `4 MS^(-1)` Applying the principle of conservation of linear momentum, `m_1u_1 + m_2u_2 = (m_1 + m_2)v , 10 u_1+ 5 xx 0 = (10 + 5) 4` `10 u_1 = 60 " or " u_1 = 60/10 = 6 ms^(-1)`. |
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