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A 10.0 litre container is filled with a gas to a pressure of 2.00 atm at `0^(@)C`. At what temperature will the pressure inside the container be 2.50 atm ? |
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Answer» As volume of the container remains constant, applying pressure-temperature law, viz., , `(P_(1))/(T_(1))=(P_(2))/(T_(2))`, we get `(2 atm)/(273 K)=(2.50 atm)/(T_(2))" or " T_(2)=341 K=341-273^(@)C=68^(@)C` |
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