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A 10.0 French fry temperature changes by 37 degree Celsius if the final length of the FRI is 50.0 3 cm calculate the coefficient of thermal linear expansion of the fry.pls tellI will mark as brainlist ans |
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Answer» Answer: N 2
O
(g)⇋2NO 2
(g) 1 MOL 0 mol --------------- initially (1-0.5) mol 2x0.5 mol ----------- at eqbm Total NUMBER of moles =0.5+1=1.5mol P N 2
O 4
= 1.5 0.5
×1atm= 3 1
atm P NO 2
= 1.5 1
×1atm= 3 2
atm According to low of chamical EQUILIBRIUM K p
= P N 2
O 4
P NO 2
2
= ( 3 1
) ( 3 2
) 2
=1.33atm We know △G ∘ =−2.303RTlogK p
−−−(1) Substituting the volume equation (1) we get △G ∘ =−2.303×(0.082JK −1 mol −1 )×(333K)×log(1.33) =−7.79 atm.lit |
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