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A 1 : 2 mixture (by mole) of ethanol and propanol exerts a vapour pressure of 250 mm Hg. The vapour pressure of propanol in solution is 200 mm Hg, then the vapour pressure of pure ethanol is (in mm Hg)

Answer» A 1 : 2 mixture (by mole) of ethanol and propanol exerts a vapour pressure of 250 mm Hg. The vapour pressure of propanol in solution is 200 mm Hg, then the vapour pressure of pure ethanol is (in mm Hg)


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