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A 0.10 kg block oscillates back and forth along a horizontal surface. Its displacement from the origin is given by: x=(10cm)cos[(10rads)t+π2rad] . What is the maximum acceleration experienced by the block [AMU (Engg.) 2000] |
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Answer» A 0.10 kg block oscillates back and forth along a horizontal surface. Its displacement from the origin is given by: x=(10cm)cos[(10rads)t+π2rad] . What is the maximum acceleration experienced by the block [AMU (Engg.) 2000] |
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