A 0.1 M aqueous solution of a monoprotic acid (ρ=1.01g/cm3) is 5% ion – InterviewSolution

1.	A 0.1 M aqueous solution of a monoprotic acid (ρ=1.01g/cm3) is 5% ionized. Calculate the freezing point of the solution.Given:Molecular weight of acid=300 g mol−1Kf(H2O)=1.86∘C/m:
Answer» A $0.1 M$ aqueous solution of a monoprotic acid $(ρ = 1.01 g / c m^{3})$ is $5 %$ ionized. Calculate the freezing point of the solution. Given: $Molecular weight of acid = 300 g m o l^{- 1}$ $K_{f} (H_{2} O) = {1.86}^{\circ} C / m :$

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