1.

9x^2+27x-162=0 factors for the middle no?

Answer»

9x²+27x-162=0; 9(x²+3x-18)=0; x²+3x-18=0; x²+6x-3x-18=0(By SPLITTING the middle term); x(x+6)-3(x+6)=0; (x-3)(x+6)=0; x=(-6);3; Please mark the ANSWER as BRAINLIEST.



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