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(9t-7)(t+6)=(3t-4)(3t+5) |
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Answer» (9t-7)(t+6)=(3t+5)(3t-4)We move all terms to the left:(9t-7)(t+6)-((3t+5)(3t-4))=0We multiply parentheses ..(+9t^2+54t-7t-42)-((3t+5)(3t-4))=0 We calculate terms in parentheses: -((3t+5)(3t-4)), so:(3t+5)(3t-4)We multiply parentheses ..(+9t^2-12t+15t-20)We get rid of parentheses9t^2-12t+15t-20We add all the numbers together, and all the variables9t^2+3t-20Back to the equation:-(9t^2+3t-20) We get rid of parentheses9t^2-9t^2+54t-7t-3t-42+20=0We add all the numbers together, and all the variables44t-22=0We move all terms containing t to the left, all other terms to the right44t=22t=22/44t=1/2 |
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