9a² + 4b² + 16c² + 12ab - 16bc - 24ca=> ( - 3a )² + ( - 2b )² + ( 4 C )² + 2[ ( -3a × -2b ) + ( -2b × 4c ) + ( 4c × - 3a ) ] We KNOW, a² + b² + c² + 2( ab + BC + ca ) = ( a + B + c )²Hence, . => [ ( -3a ) + ( -2b ) + ( 4c ) ]²=> ( -3a - 2b + 4c )²
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