1.

-9ab (a²+12a+35) ÷ 3ab(a+5)

Answer»

\frac{ - \cancel{9ab}\:^{3}(a² + 12a + 35)}{\cancel{3ab}(a + 5)}  \\  \\  \frac{-3(a² + 12a + 35)}{(a + 5)}  \\  \\  \frac{-3(a² +7a + 5a+35)}{a+5}  \\  \\  \frac{-3(a+7)\cancel{(a+5)}}{\cancel{(a+5)}}  \\  \\ -3a - 21



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