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`._(92)U^(235) + n rarr` fission product + neutron `+ 3.20 xx 10^(-11) J`. The energy released when 1g of `._(92)U^(235)` undergoes fission isA. `12.75 xx 10^(8) kJ`B. `18.60 xx 10^(9) kJ`C. `8.21 xx 10^(7) kJ`D. `6.55 xx 10^(6) kJ` |
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Answer» Correct Answer - C `1g U-235 = (6.023 xx 10^(23))/(235)` atoms `:.` Energy released `= 3.2 xx 10^(-11) xx (6.023 xx 10^(23))/(235) J` `= 8.21 xx 10^(1) J = 8.2 xx 10^(7) kJ` |
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