Question:-What is the distance travelled by a body thrown upward with a speed 20 m/s under the effect of gravity in the first second of its motion.(given g=10m/s2) and also find the distance covered at first second.Given:-A body is thrown upward with a speed 20 m/s under the effect of gravity in the first second of its motion.ACCELERATION due to gravity is 10 m/s².To Find:-Distance covered by the object at the first second.SoLuTioN:-A body is thrown upward with a speed 20 m/s under the effect of gravity in the first second of its motion. Means, the initial velocity of the body i.e. U is 20 m/s.Also, the acceleration due to gravity i.e. g is 10 m/s². But as the body is thrown against the gravity. So, acceleration due to gravity is -10 m/s².We have to find the distance covered by the object at the first second. We can say that given one is 1 second.At the highest POINT, final velocity i.e. v will be 0 m/s.Using the Second Equation Of Motion,Substitute the KNOWN in the above FORMULA,Therefore, the distance covered by the body is 15 m.