1.

9. The numerator of a fraction is 2 less thanits denominator. If 3 is added to each of thenumerator and the denominator, the fractionincreases by 1/18 find the fraction.​

Answer»

LET the denominator of the REQUIRED fraction be x.

-> Numerator will be x - 2.

According to the condition,

\frac{x - 2 + 3}{x + 3}  =  \frac{x - 2}{x} +  \frac{1}{18}

=  > \frac{x + 1}{x + 3}  -  \frac{x - 2}{x} =  \frac{1}{18}

=  >  {x}^{2}  - 3x - 108 = 0

=  >  {x}^{2}  - 12x + 9x - 108 = 0

-  > (x - 12)(x + 9) = 0

x = 12 \: or \: x =  - 9

Therefore the required fraction is

\frac{10}{12} \: or \:  \frac{ - 11}{ - 9}

=  \frac{11}{9}



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