9. The angle of depression of a ship from the top of a 30 m tall tower

1.	9. The angle of depression of a ship from the top of a 30 m tall tower is 30°. Find the distance of theship from the tower.
Answer» tan30=qr/pq; 1/V3=h/30; hV3=30; h=30/V3 = 30/ v3 x V3/ V3=30V3/3=10V3 let, AB=30m BC=X <C=30° ABC got to be the same as AB by BC=tan 30° =)30 by x= 1 by wrute3 =)x=30wrute3 tan30=pq/qr; 1/V3=30/x; x=30V3

9. The angle of depression of a ship from the top of a 30 m tall tower is 30°. Find the distance of theship from the tower.

Answer»

tan30=qr/pq; 1/V3=h/30; hV3=30; h=30/V3 = 30/ v3 x V3/ V3=30V3/3=10V3

let, AB=30m BC=X <C=30° ABC got to be the same as AB by BC=tan 30° =)30 by x= 1 by wrute3 =)x=30wrute3

tan30=pq/qr; 1/V3=30/x; x=30V3