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9. One of the exterior angles of a triangle is 70° and the interior oppositeangles are in the ratio 3:4. Find the angles of the triangle.​

Answer»

Let interior opposite ANGLES be 3x and 4X

And,

Sum of interior opposite angles = exterior angle.

3x + 4x = 70°

7x = 70

x = 70/7

x = 10

So, 3x = 3 × 10 = 30°

4x = 4 × 10 = 40°

Now, to find third angle

Let 3rd angle be 'x'

we know,

sum of all angles of a ∆ are 180°

30° + 40° + x = 180°

70° + x = 180°

x = 180 - 70

x = 110°

So, 3 angles will be 30°, 40° and 110°


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