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9. In the adjoining figure, ABCD is acyclic quadrilateralin whichzBCD=100° and <ABD = 50°. FindLADB10050 |
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Answer» The Quadrilateral is cyclic , so, angle C + angle A = 180° => angle DAB = 180°-100° = 80° now in ∆ADB , sum of angles are 180° so , angle ADB = 180° -50-80 = 50° |
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