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9. In the adjoining figure, ABCD is acyclic quadrilateralin whichzBCD=100° and <ABD = 50°. FindLADB10050

Answer»

The Quadrilateral is cyclic , so, angle C + angle A = 180°

=> angle DAB = 180°-100° = 80°

now in ∆ADB , sum of angles are 180°

so , angle ADB = 180° -50-80 = 50°



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