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9) Find three consecutive odd numbers whose sum is 147. |
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Answer» Step-by-step explanation: Let the required numbers be (2x + 1), (2x + 3) and (2x + 5). ATQ, (2x+1) + (2x+3) + (2x+5) = 147. > 6x + 9 = 147 > 6x = 147 - 9 > 6x = 138 > x = 138/6 = 23 (2x = 23 *2 = 46) Hence, the numbers are (46+1), (46+3) and (46+5) = 47, 49 and 51 Read more on Brainly.in - https://brainly.in/question/350700#readmore Step-by-step explanation: Let the required numbers be (2x + 1), (2x + 3) and (2x + 5). ATQ, (2x+1) + (2x+3) + (2x+5) = 147. > 6x + 9 = 147 > 6x = 147 - 9 > 6x = 138 > x = 138/6 = 23 (2x = 23 *2 = 46) Hence, the numbers are (46+1), (46+3) and (46+5) = 47, 49 and 51 Read more on Brainly.in - https://brainly.in/question/350700#readmore Let the first odd number be x+1Second odd number x+3Third odd number x+5A/Qx+1+x+3+x+5=1473x+9=1473x=138 |
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