9. Find the smallest square number that is divisible by each of the nu

1.	9. Find the smallest square number that is divisible by each of the numbers10: Find the smallest square number that is divisible by each of the numbers & 15 and 20
Answer» Let us find LCM of 4, 9 and 104 = 2 x 29 = 3 x 310 = 5 x 2So, LCM = 22x 32x 5 = 180Now the LCM gives us a clue that if 180 is multiplied by 5 then it will become a perfect square.The Required number = 180 x 5 = 900 Plz like my answer Plz accepted as best Plz accepted as best bottom click and yes to accepted as best Plz 9.ans=Answer: 900 Step-by-step explanation: First let us take the lcm for the three no. So the lcm is 180 In the lcm, 5 doesn't have a pair So, 180×5=900 Hence,the required answer is 900 the correct answer is 900 900 is the answer to the question you have asked

9. Find the smallest square number that is divisible by each of the numbers10: Find the smallest square number that is divisible by each of the numbers & 15 and 20

Answer»

Let us find LCM of 4, 9 and 104 = 2 x 29 = 3 x 310 = 5 x 2So, LCM = 22x 32x 5 = 180Now the LCM gives us a clue that if 180 is multiplied by 5 then it will become a perfect square.The Required number = 180 x 5 = 900

Plz like my answer Plz accepted as best Plz accepted as best bottom click and yes to accepted as best Plz

9.ans=Answer:

900

Step-by-step explanation:

First let us take the lcm for the three no.

So the lcm is 180

In the lcm, 5 doesn't have a pair

So, 180×5=900

Hence,the required answer is 900

the correct answer is 900

900 is the answer to the question you have asked

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