9. At what distance does a man 5 ft in height, subtend an angle of15"?

1.	9. At what distance does a man 5 ft in height, subtend an angle of15"?
Answer» As we know that, 1'=60''=>1''=(1/60)'. and 15''=(15×1/60)'=(1/4)' again, we know that 1°=60'=>1'=(1/60°) so (1/4)'=(1/240)°. =(1/240×π/180)c. let the angle between the man and the ground be x°. Then tan(π/43200)=167.64/h =>.000072=167.64/h =>h=2328333cm. (approx).where h is the distance from the man to the angle.

Answer»

As we know that, 1'=60''=>1''=(1/60)'.

and 15''=(15×1/60)'=(1/4)'

again, we know that 1°=60'=>1'=(1/60°)

so (1/4)'=(1/240)°. =(1/240×π/180)c.

let the angle between the man and the ground be x°.

Then tan(π/43200)=167.64/h

=>.000072=167.64/h

=>h=2328333cm.

(approx).where h is the distance from the man to the angle.

Discussion