83) A ship sails out from jetty to a mark at the rate of 15km/hr. and

1.	83) A ship sails out from jetty to a mark at the rate of 15km/hr. and sails back to jetty at the rate of 10km/hr. Theaverage speed of sailing isA) 5 km/hrB) 12 km/hrC) 12.5 km/hrShife: SpiralJelly-spedD) 25 km/hr
Answer» ANSWER: (C) 12.5 km/hr Step-by-step explanation: Let u=15 km/hr amd v=10 km/hr for the ship. we know that, AVERAGE Velocity = 1/2(v+u) so, applying the formula *Average Velocity = 1/2(v+u)* *=> Average Velocity = 1/2(15+10) km/hr* *=> Average Velocity = 1/2 x 25 km/hr* *=> Average Velocity = 12.5 km/hr* *I m very happy to help you out. Take some time to Mark it as The BRAINLIEST Answer If it helps And That WOULD really make Me Happy and My explaination successful ! Have A good Day Buddy :)*

83) A ship sails out from jetty to a mark at the rate of 15km/hr. and sails back to jetty at the rate of 10km/hr. Theaverage speed of sailing isA) 5 km/hrB) 12 km/hrC) 12.5 km/hrShife: SpiralJelly-spedD) 25 km/hr

Answer»

ANSWER:

Step-by-step explanation:

Let u=15 km/hr amd v=10 km/hr for the ship.

we know that, AVERAGE Velocity = 1/2(v+u)

so, applying the formula

Average Velocity = 1/2(v+u)

=> Average Velocity = 1/2(15+10) km/hr

=> Average Velocity = 1/2 x 25 km/hr

=> Average Velocity = 12.5 km/hr

I m very happy to help you out. Take some time to Mark it as The BRAINLIEST Answer If it helps And That WOULD really make Me Happy and My explaination successful ! Have A good Day Buddy :)

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83) A ship sails out from jetty to a mark at the rate of 15km/hr. and sails back to jetty at the rate of 10km/hr. Theaverage speed of sailing isA) 5 km/hrB) 12 km/hrC) 12.5 km/hrShife: SpiralJelly-spedD) 25 km/hr​

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83) A ship sails out from jetty to a mark at the rate of 15km/hr. and sails back to jetty at the rate of 10km/hr. Theaverage speed of sailing isA) 5 km/hrB) 12 km/hrC) 12.5 km/hrShife: SpiralJelly-spedD) 25 km/hr