1.

8000 kgs vehicle moving with a speed of 20 metre per second is brought to rest in a distance of 50 metres find the acceleration calculate the unbalanced force acting on the vehicle

Answer»

Mass (m) = 8000 kgInitial Velocity (u) = 20 m/sFinal Velocity (V) = 0 m/s (since it is coming to rest)Distance (s) = 50 mv^2 = u^2 + 2as, where, acceleration = a0 = (20)^2 + 2(a)500 = 400 + 100a-400 = 100aa = -400/100a = -4 m/s^2f = m.a, where FORCE = f = 8000 ( -4) = -32000 NewtonThanks and have a great AFTERNOON, :)



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