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80. When \( Cl _{2} \) gas reacts with hot and concentrated sodium hydroxide solution, the oxidation number of chlorine changes from(1) zero to \( +1 \) and zero to \( -5 \)(2) zero to \( -1 \) and zero to \( +5 \)(3) zero to \( -1 \) and zero to \( +3 \)(4) zero to \( +1 \) and zero to \( -3 \) |
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Answer» The reaction of chlorine gas with hot and concentrated sodium hydroxide solution is 3Cl2 + 6NaOH⟶NaClO3 + 5NaCl+3H2O Oxidation number of Cl is 0 in Cl2, −1 in NaCl and +5 in NaClO3 So the oxidation number of chlorine changes from Zero to -1 and Zero to +5. |
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