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8/y+3=10find the value of y​

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\implies\sf \dfrac{8}{y} + 3 = 10

\implies\sf \dfrac{8}{y} = 10 - 3

\implies\sf \dfrac{8}{y} = 7

\implies\sf8 = 7 \times y

\implies\sf8 = 7y

\implies\sf \dfrac{8}{7} = y

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